Does Energy Gain NEED To Go Back to the Positive?

[Jim Mac]

Ok so I took my pulse motor and induced an output coil.  Rectified the output and ran the DC+ output to the Negative of a separate battery.  Out the positive of a battery, then to a load.

I am certain we can ABSOLUTELY send gain back to the negative of a battery. 

The DC output (any voltage) will series with the batteries voltage.  And as we spin the generator, the load gets more power (obviously).

So if we have a circuit that has a "gain" that goes back to the negative of the source, that gain will series with the source voltage and re-enter the system.

[unimmortal]

This scenario is the only one I haven't tried - adding in a second battery to bridge the induced generator flow back to source - Thanks Jim!

I wonder how the back-emf from the motor pulse can be used with this setup...

[magluvin]

in a battery, there is one direction of current flow to discharge and one direction to charge. to charge, electrons need to be pulled from the positive and pumped into the negative. similar to a cap. if you think your sending energy to only the positive or negative of the battery, you are mistaken.
if it were a tank of air, letting air out releases energy(and you would be better to use that output to do something or that energy is wasted) and pumping air in is storing energy. only one way to do either...

mags

[Jim Mac]

in a battery, there is one direction of current flow to discharge and one direction to charge. to charge, electrons need to be pulled from the positive and pumped into the negative. similar to a cap. if you think your sending energy to only the positive or negative of the battery, you are mistaken.
if it were a tank of air, letting air out releases energy(and you would be better to use that output to do something or that energy is wasted) and pumping air in is storing energy. only one way to do either...

mags

Of course sending energy into the negative does NOT charge the battery.  But any energy you send into the negative from a separate source will sum with the voltage of the battery and exit the positive with higher amplitude.  Exactly like series connecting batteries.

So if a 12V battery was powering a 10 ohm resistor, that battery is putting out 1.2 amps.  Not if a generator was sending 10V to the negative of that same batter and has the required amperage behind it,  you would have 22V coming from that 12V battery positive.   So now 2.2 amps would be hitting that load.  But the battery will only be taxed 12V @ 1.2 amps.

The whole point was, is any "gain" in a circuit is directed at the negative of a source battery may not be a bad thing at all.  It just depends on the circuit's intentions and "IF" that extra power is being delivered when it is Needed or Unneeded.

[magluvin]

if the battery and "generator" are in series, then the battery current would be 2.2amps. the whole loop of components has 2.2amps.

mags

[Jim Mac]

if the battery and "generator" are in series, then the battery current would be 2.2amps. the whole loop of components has 2.2amps. 

mags

Not really..  The FWBR negative has a split path where the current can flow.  The battery supplied current does not need to flow through the coil to get back to the battery. The FWBR allows the batteries current to go straight back to the battery and the Generator's current to go straight back to the coil.

The batteries current will never flow through the coil because it would be forced to flow through the load twice. So the battery, Load, and FWBR would have 2.2 amps wile the coil remains 1 amp