04-17-2026, 05:17 AM
(This post was last modified: 04-17-2026, 05:50 AM by captainSensible.)
I imagine you'd want to start with a small or moderate sized core to begin with, instead of going out and buying the largest one you can find..
The goal is to saturate the core so that means lots of Amp-turns to generate the flux. Thus the switching device (probably a mosfet) must handle the large peak currents.
More turns, less amps required and vice versa.
A smaller inductor and/or operation at higher voltage will allow higher frequency operation, the advantage being less turns of wire required.
Higher voltage will give a faster current rise time (i/t = V/L)
Its essential to have a decent capacitor across the power supply to provide the peak current. By decent that doesn't necesarily mean large (although it would for low frequencies), but just something with a low ESR that can supply the current and a good quality dielectric such as power film capacitor.
I'm guessing a 1:1 ratio would be best for the transformers otherwise you could end up with too high a voltage on one side. E.g. if mains transformer say 240 to 12V the ratio is 20:1 so if the load volts is on the low side and reaches e.g 50V then the saturation side will reach 20 times that which will cause breakdown.! Alternatively using the low voltage side as saturation side will still cause high volts at the load side due to needing a load resistance much greater than winding resistance, meaning again it could cause breakdown.
Standard mains transformers are not designed to operate in saturation so I think you're always going to have a problem with them over-volting or wasting too much power when you try to saturate them in this type of circuit. (But they work fine as saturable reactors because the load limits the max current/power)
And of course a saturable reactor is operating with steady-state sinusoidal signals whereas here we are using 'switched mode' type of operation
The goal is to saturate the core so that means lots of Amp-turns to generate the flux. Thus the switching device (probably a mosfet) must handle the large peak currents.
More turns, less amps required and vice versa.
A smaller inductor and/or operation at higher voltage will allow higher frequency operation, the advantage being less turns of wire required.
Higher voltage will give a faster current rise time (i/t = V/L)
Its essential to have a decent capacitor across the power supply to provide the peak current. By decent that doesn't necesarily mean large (although it would for low frequencies), but just something with a low ESR that can supply the current and a good quality dielectric such as power film capacitor.
I'm guessing a 1:1 ratio would be best for the transformers otherwise you could end up with too high a voltage on one side. E.g. if mains transformer say 240 to 12V the ratio is 20:1 so if the load volts is on the low side and reaches e.g 50V then the saturation side will reach 20 times that which will cause breakdown.! Alternatively using the low voltage side as saturation side will still cause high volts at the load side due to needing a load resistance much greater than winding resistance, meaning again it could cause breakdown.
Standard mains transformers are not designed to operate in saturation so I think you're always going to have a problem with them over-volting or wasting too much power when you try to saturate them in this type of circuit. (But they work fine as saturable reactors because the load limits the max current/power)
And of course a saturable reactor is operating with steady-state sinusoidal signals whereas here we are using 'switched mode' type of operation

