Join us in the search for Free Energy. Share your experiments and discoveries, post your build logs, and discuss.

We have a strict No-Troll policy. So you can post without fear of being ridiculed.

New Members- Check Your Spam Folder For Activation Link

Please read our Rules. Any problems or suggestions- Contact Us

 

Other Overunity Forums:

Overunity Machines   ||   Overunity Research



Thread Rating:
  • 0 Vote(s) - 0 Average
  • 1
  • 2
  • 3
  • 4
  • 5
Conversion of atmospheric heat into electricity by using Venturi effct.
#1
I am an Indian inventor. For a long time, I am continuing personal research about a theoretical machine that can extract atmospheric heat and convert that into useful power. Recently, while searching net, I have found out that the necessary machinery is already available in market. In short, the machine now can be built easily.
At present, I have completed the CAD drawing and done some ANSYS simulation testing. As per the latest simulation where the RPM was set of 3600, the torque was found to be around 1.52 for a machine of 35 cm diameter and the input wind velocity was set to be 6 m/s. For me, this is promising result and I can say that no wind turbine in anywhere around the world of that little diameter can generate such torque at
this RPM.
In such a scenario, I am requesting for suggestion from others regarding how to continue my research. At present, what I am facing mainly is financial crunch as I am doing all the research at my own cost and all my funds are almost exhausted.
Friends, kindly suggest what to do now.
#2
Conversion of atmospheric heat into electricity by using Venturi effect ?

can extract atmospheric heat and convert that into useful power ?

the RPM was set of 3600
the torque was found to be around 1.52 ... 1.52 what, Newtons ?
for a machine of 35 cm diameter
the input wind velocity was set to be 6 m/s. ... what is the wind velocity source ?
6 m/s = 13.42162 mph

Can you give more details ?
#3
(11-19-2023, 04:13 PM)floor Wrote: Conversion of atmospheric heat into electricity by using Venturi effect ?

can extract atmospheric heat and convert that into useful power ?

the RPM was set of 3600
the torque was found to be around 1.52 ...    1.52 what, Newtons ?
for a machine of 35 cm diameter
the input wind velocity was set to be 6 m/s.  ... what is the wind velocity source ?
6 m/s = 13.42162 mph

Can you give more details ?

The torque is 1.52 Newton-meter. Just multiply that with RPS i.e. RPM/60 i.e. (3600/60) together with 6.28, you will get the possible output. The basic output formula is torque X RPS (Rounds per secon) X 6.28. You can check that in any book of engineering or physics. What more details do you want?
#4
Ok
1.5 Newton-meter = 1.5 joules
and
3,600 rpm
or
6.28 rotations per second ...

6.28 x 1.5 = 9.42 joules per second
or
9.42 watts.
for a machine of 35 cm diameter
in a 6 m/s. or 13.42 mph wind.

 Thanks

Very impressive.

Do you need to build a proto type next ?
#5
(11-27-2023, 11:12 AM)floor Wrote: Ok
1.5 Newton-meter = 1.5 joules
and
3,600 rpm
or
6.28 rotations per second ...

6.28 x 1.5 = 9.42 joules per second
or
9.42 watts.
for a machine of 35 cm diameter
in a 6 m/s. or 13.42 mph wind.

 Thanks

Very impressive.

Do you need to build a proto type next ?

First, I want to correct you. 3600 RPM means 60 rotations per second. Now, output is 1.52 X 60 X 6.28, kindly do the math yourself. And of course I want to build a prototype next. I have expected better reply from you. I am tired of your wrong math.
#6
Ok correction
1.5 Newton-meter = 1.5 joules
and
3,600 rpm
or
60 rotations per second ...

60 rotations per second x 1.5 Joules per rotation = 90 joules per second
or
90 watts.
for a machine of 35 cm diameter
in a 6 m/s. or 13.42 mph wind force.

 Thanks 

Do you intend to patent or open source ?
#7
(11-27-2023, 12:38 PM)floor Wrote: Ok correction
1.5 Newton-meter = 1.5 joules
and
3,600 rpm
or
60 rotations per second ...

60 rotations per second x 1.5 Joules per rotation = 90 joules per second
or
90 watts.
for a machine of 35 cm diameter
in a 6 m/s. or 13.42 mph wind force.

 Thanks 

Do you intend to patent or open source ?
Of course I intend to apply for patent. I have already applied for provisional patent application. And, again, you have calculated it wrongly. The real power output = 1.52 X 60 X 6.28. Kindly multiply this 90 with 6.28 and you will get the real output.
#8
Ok RevI

You have expected better reply from me and you are tired of my wrong math.
Why is it that you say "Of course" when you state that you intend to apply for patent."

Your bad attitude = I'm outa here...
#9
This thread is now closed and locked.

Remember, this is an open-source forum. If you are not ready to share details of your project so others can reproduce it, then it has no place on this forum.


Forum Jump:


Users browsing this thread: 1 Guest(s)