11-10-2024, 03:10 PM
(11-10-2024, 07:53 AM)unimmortal Wrote: Hey Jim, I believe I have an answer as to why you are seeing the current on the negative. But I'd need to see how you've wired it up to be sure.
What you've done is create a current sink! By only offering up half a wave to create a field, the ether is kindly adding in the missing negative bit.
I'm not quite sure if this happens at the moment of induction of the first coil or the moment of reaction by the middle coil or at counter reaction by the first coil.
Oscillating over the bloch wall is where the magic is, you're tapping ether there.
You put in a half wave and got a whole one back!
I think that's partially correct. But there's more I haven't shown yet.. Once I present it and you digest it, it should be more clear.
With 2 coils and two 1/2 waves the same polarity 180 degrees out of phase is when the "Magical current" appears. In this configuration, I can remove the negative feed from the stereo amplifiers and the circuit (and amplifiers) run perfectly as if there was a ground. So the declining wave gives the Amplifiers it's ground or return wire right through the output terminals even though the wave is 1 positive polarity.
Basically, the current from 1 channel to the next is looping.. So the induced EMF current that is generated adds to the current in the loop.
Even though I still can not attain decent output from it yet. If you think about it, switching polarities causes double as much Peak to Peak.. If we had a 12V source and switched polarities, we get +12 and -12, giving us a 24V swing. But from Zero to 12 is only 1/2 as much swing, so the output suffers..
I have something else on my bench at the moment, but I will be coming back to this I am sure, so I will post a video of the circuit working without a ground on the amplifiers at that time.. (unless there is overwhelming desire to see it)..
I will add, the whole powering the amps with no ground wire only works if both amp's negative feeds are tied together, because the path needs to be complete ofcourse.